rx^3+5x^2+4x+20=0

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Solution for rx^3+5x^2+4x+20=0 equation:


Simplifying
rx3 + 5x2 + 4x + 20 = 0

Reorder the terms:
20 + rx3 + 4x + 5x2 = 0

Solving
20 + rx3 + 4x + 5x2 = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + rx3 + 4x + -20 + 5x2 = 0 + -20

Reorder the terms:
20 + -20 + rx3 + 4x + 5x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + rx3 + 4x + 5x2 = 0 + -20
rx3 + 4x + 5x2 = 0 + -20

Combine like terms: 0 + -20 = -20
rx3 + 4x + 5x2 = -20

Add '-4x' to each side of the equation.
rx3 + 4x + -4x + 5x2 = -20 + -4x

Combine like terms: 4x + -4x = 0
rx3 + 0 + 5x2 = -20 + -4x
rx3 + 5x2 = -20 + -4x

Add '-5x2' to each side of the equation.
rx3 + 5x2 + -5x2 = -20 + -4x + -5x2

Combine like terms: 5x2 + -5x2 = 0
rx3 + 0 = -20 + -4x + -5x2
rx3 = -20 + -4x + -5x2

Divide each side by 'x3'.
r = -20x-3 + -4x-2 + -5x-1

Simplifying
r = -20x-3 + -4x-2 + -5x-1

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